Iteration cycle of a code

3 次查看(过去 30 天)
Hi !!! Have a nice day.
I have a code that starts with the generation of a matrix A,
after a numerical process at the end I have a matrix B
A = [a, b, c,… ..
q, w, r,….];
instructions
instructions
instructions
instructions
instructions
instructions
B = [d, e, f,….
and, u, I, ...];
At the end of the numerical process I have matrix B, immediately
the values of B are assigned to A in this way
A = B
What instruction I need to do to generate this cycle N times, that this; the results of B introduce them to input A?
I hope you understand what I want to do
Thank you
  6 个评论
Adam Danz
Adam Danz 2019-12-5
编辑:Adam Danz 2019-12-5
" I want to update the values of A with the resulting matrix B"
So you want to completely overwrite A with whatever is stored in B on each iteration.
But this I have not been able to achieve"
Why not? What specific problems have you faced?
Again, a simple example of expected input and outputs usually saves quite a bit of time and dialog.
Ricardo Gutierrez
Ricardo Gutierrez 2019-12-5
You are right.
I should check my code.
Thank you very much for your patience and your help.

请先登录,再进行评论。

采纳的回答

meghannmarie
meghannmarie 2019-12-5
Can you show your code? Make sure you are initally setting A before the for loop. If I am understanding the problem, it should look something like this:
A = [a,b,c;q,w,r];
for n = 1:5
% instructions
% instructions
% instructions
B = [d,e,f;l,m,n]
A = B;
end
  5 个评论
meghannmarie
meghannmarie 2019-12-5
Is variable A part of the input into building variable B? There must be an error in your code, I do not know how to troubleshoot without code.
Ricardo Gutierrez
Ricardo Gutierrez 2019-12-5
Thank you very much.
You are right there must be some error in my code.
Thank you for your patience and attention.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

产品


版本

R2014a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by