funs_cell = {'sin', 'cos', 'tan', 'sinh'};
markers = {'+', 'o', '*', 'x', 's'};
funs = cellfun(@str2fun, funs_cell, 'uniform', 0);
for K = 1 : length(funs)
plot(x, funs{K}(x), markers{K}, 'DisplayName', funs_cell{K});
hold on
end
plot with input arguments
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i want to subplot 4 string containg cell array from ( sin, cos, tan,sinh) and vector (+,o,*,x,s) and the mathmatical function should be ploted in interval (-2pi,2pi)with step 0.3
采纳的回答
Walter Roberson
2019-12-5
33 个评论
Roger Nadal
2019-12-5
If I pass more value in fun_cell then it should select only four value while passing function so how it should work?
Roger Nadal
2019-12-6
yes i want to select random four and it should plot 4 subplot in one figure like function
abc({sin', 'sinh', 'cos', 'cosh'}, ['o', 'x', 's', '*']) it should plot four in one figure.
Walter Roberson
2019-12-6
It would be better if the markers were passed as a cell array rather than as a character vector. With a cell array you would have the option of passing line styles and line colors as well.
function abc(funs_cell, markers)
funs = cellfun(@str2fun, funs_cell, 'uniform', 0);
order = randperm(length(funs), 4); %4 of them at random
for K = order
subplot(2,2, K)
plot(x, funs{K}(x), markers{K});
title(funs_cell{K});
end
end
Roger Nadal
2019-12-6
编辑：Roger Nadal
2019-12-6
is it str2fun or str2func? and how to pass line colour using cell array?
Walter Roberson
2019-12-6
Ah, str2func.
I was sure I had tested before; I must have transcribed it wrong when I posted.
abc({sin', 'sinh', 'cos', 'cosh'}, {'r-o', 'b-x', 'g-s', 'k--*'})
Roger Nadal
2019-12-6
is there is any way to solve this without using any loop?and i want to pass markers argument and colours argument in vector with [ ] brace indexing
Walter Roberson
2019-12-6
You could use [] indexing if you pass "" delimited string objects.
If you restrict to character vectors then when you use ['o', 'x', 's', '*'] then MATLAB cannot tell that apart from the case where you passed 'oxs*' as a single character vector. You would lose the flexibility of having specifications of different length. You could handle the case where the user always passed exactly the same number of characters per specification. For example you would not be able to specify dashed line with '--' unless the user always passed two characters for the line type even when they only wanted '-' or ':' line type.
Roger Nadal
2019-12-6
编辑：Roger Nadal
2019-12-6
And if I have to pass colour as third argument in function so should I just define it in function and plot it? abc({'sin','cos','tan','sinh'},['b','r','g','y'],['o','x','*','s']) so the first argument will be cell array and other two will be vector. and how to plot step 0.4 for each marker.
Walter Roberson
2019-12-7
I don't know why you insist on not using a loop. I don't know why you insist on using character vectors for your markers and colors instead of the much more flexible cell array. But I no longer have patience to lead you through this, so I will give you what you are asking for, even though it is not what you should be using.
function abc(funs_cell, colors, markers)
x = -2*pi:0.4:2*pi;
order = randperm(length(funs),4); %random order
fun = str2fun(funs_cell{order(1)});
subplot(2,2,1);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(1), 'Marker', markers(1));
title(funs_cell{order(1)});
fun = str2fun(funs_cell{order(2)});
subplot(2,2,2);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(2), 'Marker', markers(2));
title(funs_cell{order(2)});
fun = str2fun(funs_cell{order(3)});
subplot(2,2,3);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(3), 'Marker', markers(3));
title(funs_cell{order(3)});
fun = str2fun(funs_cell{order(4)});
subplot(2,2,4);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(4), 'Marker', markers(4));
title(funs_cell{order(4)});
end
Walter Roberson
2019-12-7
function abc(funs_cell, colors, markers)
x = -2*pi:0.4:2*pi;
order = randperm(length(funs_cell),4); %random order
fun = str2fun(funs_cell{order(1)});
subplot(2,2,1);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(1), 'Marker', markers(1));
title(funs_cell{order(1)});
fun = str2fun(funs_cell{order(2)});
subplot(2,2,2);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(2), 'Marker', markers(2));
title(funs_cell{order(2)});
fun = str2fun(funs_cell{order(3)});
subplot(2,2,3);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(3), 'Marker', markers(3));
title(funs_cell{order(3)});
fun = str2fun(funs_cell{order(4)});
subplot(2,2,4);
plot(x, fun(x), 'LineStyle', '-', 'Color', colors(4), 'Marker', markers(4));
title(funs_cell{order(4)});
end
Roger Nadal
2019-12-7
is there is any way to change points for x axes like in plot the points of x axes is [-5 5] instead i want [-10 10].
Walter Roberson
2019-12-7
xlim([-10 10])
However you should be considering changing the definition of x instead. Your requirements were that it be -2*π to 2*π. Did that requirement change?
Roger Nadal
2019-12-7
编辑：Roger Nadal
2019-12-7
no the function should plot on interval [-2pi ,2pi] but the x axes i want [-10 10]. the order of plot is different than argument pass in fuction {sin', 'sinh', 'cos', 'cosh'} the plot order is sinh,cosh,sin,cos.
Walter Roberson
2019-12-7
xlim controls the axes boundaries no matter what is plotted inside.
You asked for random order.
Roger Nadal
2019-12-9
if i am passing more than 4 input then it should output an error input vector length is different than 4 so how to put this condition in the program?
Roger Nadal
2019-12-10
It works for math function but if I am passing 5 values in market and colour it doesn’t work for that
Walter Roberson
2019-12-10
You can combine three tests in a single if using the || operator.
This is a way to code it as a single if, but you would not be expected to work it out at the level of your homework assignment.
Walter Roberson
2019-12-11
In MATLAB,
if numel(fun_cell)||numel(color)~=4 Error(msg)
would be interpreted as
if (numel(fun_cell) ~= 0) || (numel(color) ~= 4)
error(msg)
end
MATLAB itself has absolutely no transitive operators of the form
expression1 operator1 expression2 operator2 value
being intepreted as
(expression1 operator2 value) operator1 (expression2 operator2 value)
In MATLAB you need to be explicit,
if numel(fun_cell) ~= 4 || numel(color) ~= 4
error(msg)
end
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