Open folder in Matlab

2012 10 1
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Hi
I'm trying to open folder let's call it FolderA (Here is the directory: 'C:\Users\Usersname\Desktop\FolderA')in MATLAB that constains 9 Text Documents ('.txt') of size 30000-by-10. I want to be able to choose which files I want to observe that is one Text Doument, all Text Documents or i.e. Text Douments 1, 3 and 5.
I also want to use the selected files and use i.e. vector nr. 3 and 4 in all of them.
How does one do that?

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Image Analyst
Image Analyst 2012-10-1

1 个投票

We have just the file for you in the File Exchange: http://www.mathworks.com/matlabcentral/fileexchange/10867-uipickfiles-uigetfile-on-steroids, Doug Schwarz's uipickfiles:
Description
This is a GUI application that allows multiple files or directories to be selected and allows you to manage the list (remove files, reorder, etc.) before returning. It has basic filtering as well as regular expression filtering and navigation of the file system is easy. The output is configurable (cell, struct or char arrays). It is written entirely in M and so is platform independent.

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Lily
Lily 2012-10-1
编辑：Lily 2012-10-1
This is a nice program but how do you get the files, that is load them into MATLAB? I tried using the following but that didn't work. What do you normally use? load(files)
Image Analyst
Image Analyst 2012-10-1
编辑：Image Analyst 2012-10-1
It gives you a list of filenames. Then you have to load your files one at a time.
files = uipickfiles();
storedStructure = load(files{1}); % Same for files{2}, etc.
It offers a benefit over uigetfile() in that it lets you select multiple documents, which is (I think) what you were asking about. But just like uigetfile() you still have to open files one at a time, like I did above. I don't know of any function to let you open dozens of files at once, unless you wrote your own custom function to do that. If you want to just pick one file at a time, then use uigetfile().
Lily
Lily 2012-10-1
OK, but if I were to use the load function like this:
n = input('Choose the files ');
files = uipickfiles('num',n,'out','ch')
for i = 1:n
file_(i) = load(files(i,:));
end
Could I construct a new FILE NAME, i.e. file1, file2 and so on, for every file that I load?
Image Analyst
Image Analyst 2012-10-1
Not exactly, but close
fullFileNames = uipickfiles()
for k = 1 : length(fullFileNames)
fprintf('Processing %s\n', fullFileNames{k});
storedStructure = load(fullFileNames{k});
end
Lily
Lily 2012-10-1
This is so COOL! Thx :)

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