inserting vectors into another new vector

2019 12 6
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更新时间：2019 12 7
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Hello everybod,
Let’s say I have two vectors, A=[7 17 27] and B=[13 22], and later produce a new vector C as shown in the below process:
put the first number from A as the first number in C and put the first number form B as the second number in C and then put the second number from A as the third number in C then put the second number from B as the fourth number in C and keep going on the same process to the end.
That means, I should have the final result for C as [7 13 17 22 27].
Thank you

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the cyclist
the cyclist 2019-12-6
Will B always be exactly one element shorter than A? If not, can you please tell us more detail? For example, could A be the shorter one? Do we always use all elements from both vectors?
sometimes they are the same length or B shorter than one element from A.

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JESUS DAVID ARIZA ROYETH
编辑：JESUS DAVID ARIZA ROYETH 2019-12-6

1 个投票

A=[7 17 27 35];
B=[13 22 30 15];
N = max(numel(A),numel(B));
C=[A nan(1,N-numel(A)); B nan(1,N-numel(B))];
C(isnan(C))=[]
C=C(:)'

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@JESUS DAVID ARIZA ROYETH thank you so much for answering me, but I think there is a problem. I forgot telling you that sometimes both vectors have same length. Anyhow, when I add number to B and became like [13 22 30] it works ok, but when the two matrices became like A=[7 17 27 35] and B=[13 22 30]; the answer becomes:
C= 7 17 27 35 13 22 30
while it should become C=7 13 17 22 27 30 35
Thank you again for your help.
I edited my answer, try again, did the test with several cases and it works fine

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the cyclist
the cyclist 2019-12-6

1 个投票

Here is another way:
A = [7 17 27 35];
B = [13 22 30 31];
C = [A; [B nan(numel(A)-numel(B),1)]];
C = C(1:(numel(A)+numel(B)));

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