detecting the existence of alphabetical elements
显示 更早的评论
Dear all, I would like to detect whether a string contains an alphabetical letter. A simple way of solving this problem is writing a function such as. But is there any better, more concise and faster way? Can one use, say, regular expressions and if so how?
thanks, Pat.
function flag=detect_alphabet(mystring)
referenceSet={'a','b','c','d',...,'z'};
flag=false;
for ii=1:length(mystring)
if ismember(mystring(ii),referenceSet)
flag=true;
break
end
end
采纳的回答
Perhaps best of all:
str = 'adsf2342adsfwerreoj9f3f';
str2 = '23423';
flag = any(isletter(str))
flag = any(isletter(str2))
更多回答（4 个）
Oleg Komarov
2012-10-1
regexpr(str,'[a-zA-Z]')
str = 'adsf2342adsfwerreoj9f3f';
str2 = '23423';
flag = ~isempty(regexp(str,'[A-Za-z]'))
flag = ~isempty(regexp(str2,'[A-Za-z]'))
flag = any(ismember(mystring, 'a':'z'))
But now I'm lost in the incompatibilities of Matlab versions. Perhaps it must now be:
flag = any(ismember(mystring, char('a':'z')))
Alternatively:
flag = any(mystring >= 'a' & mystring <= 'z')
Or:
flag = any(isstrprop(mystring, 'lower'))
In all cases a loop is not required.
1 个评论
Matt Fig
2012-10-1
flag = any((str>='A' & str<='Z') | ((str>='a' & str<='z')))
Patrick Mboma
2012-10-1
0 个投票
1 个评论
Image Analyst
2012-10-1
Well for what it's worth, I was going to answer isletter() until Matt beat me to it.
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2012-10-1
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