Matching X and Y co-ordinated from the reference xy

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SatyaPrakash Gupta 2019-12-9

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https://ww2.mathworks.cn/matlabcentral/answers/495659-matching-x-and-y-co-ordinated-from-the-reference-xy

编辑： Rik 2019-12-9

Hi,

I have list of XY coordinates i.e XY points for the given figure.

further i have extracted the required XY coordinates and now i want to match my current XY values present in reference XY coordinates, is it possible ?

could you please do help me here.

e.g

X = [ 1,2,3,4,5,6,7.6 , 8.9, 5.7 ..]

X = [1, 4,6,9,3,7.6,5.3.5.7... ]

so i want to compare this and get the result with the matched values i.e

final X = [7.6,5.7]

is there a way to do this ?

thank you.

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darova 2019-12-9

What about 1 and 4?

SatyaPrakash Gupta 2019-12-9

Yes i would like to return all the matched value in an array.

Please note : the dimension of X will have different size

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Answer 1

Rik 2019-12-9

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https://ww2.mathworks.cn/matlabcentral/answers/495659-matching-x-and-y-co-ordinated-from-the-reference-xy#answer_405548

编辑：Rik 2019-12-9

在 MATLAB Online 中打开

Although you can solve this with the ismember function, you are actually looking for the intersect function:

X = [1,2,3,4,5,6,7.6,8.9,5.7];
Y = [1,4,6,9,3,7.6,5.3,5.7];
X_new=intersect(X,Y)

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SatyaPrakash Gupta 2019-12-9

Hi Rik,

it will not resolve the problem because as i mentioned that i am storing the x and y values of the marked using iamfreehand() so it gives only the boundy values not the values inside the boundries, therefore i cannot use this intersect function.

could you let me know how to resolve it?

thank you

Rik 2019-12-9

编辑：Rik 2019-12-9

在 MATLAB Online 中打开

So you have a list of coordinates that form the boundary of an object? If you have a closed loop, you can use the inpolygon function to find all grid points inside your trace.

%generate an outline
u=20;
t=linspace(0,2*pi,6);x=u+u*cos(t);y=u+20*sin(t);
[X,Y]=ndgrid(1:(2*u));
L=inpolygon(X(:),Y(:),x,y);
X_in=X(L);
Y_in=Y(L);
figure(1),clf(1)
plot(x,y,'b')
hold on
plot(X(L),Y(L),'r*')
plot(X(~L),Y(~L),'r.')
axis([0 2*u+1 0 2*u+1]) %fit axis to displayed data
daspect([1 1 1])%set aspect ratio to 1