least square circle, why doesn't it work?
显示 更早的评论
Hi, so I have four data points (x and y) and I want to find A and B from least square equation Ax=B (to fit the circle's equation). I also want to solve x. I have tried the following but x the circle is not visiable. What am I doing wrong?
x = [6; 5; -1; 1];
y = [4; 6; 5; -1];
plot(x,y,'*')
% circle's equation x^2+y^2 = 2xc1+2yc2+c3
A = [2.*x,2.*y,ones(n,3)]
B = [x^2 + y^2];
c = A\B;
plot(A,B)
3 个评论
Jenny Andersen
2019-12-10
Ridwan Alam
2019-12-10
what is 'a' and 'b'?
Jenny Andersen
2019-12-10
采纳的回答
As I mentioned in your other post, your approach is not a good way to fit a circle. However, assuming you must do it this way, your main mistake was in the plotting, not in the fitting.
x = [6; 5; -1; 1];
y = [4; 6; 5; -1];
n=numel(x);
% circle's equation x^2+y^2 = 2xc1+2yc2+c3
A = [2.*x,2.*y,ones(n,1)];
B = [x.^2 + y.^2];
c = A\B;
fun=@(x,y) x.^2 + y.^2-c(1)*2*x-c(2)*2*y-c(3);
plot(x,y,'*')
hold on
fimplicit(fun,[-3,8])
hold off
axis equal
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Linear and Nonlinear Regression 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
