function with ln and log

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Tatiana Macha
Tatiana Macha 2019-12-13
编辑： Walter Roberson 2019-12-13
I am having issues with plotting.
my function is
y2 = (x-1)(ln((3^.5)/2)*x-ln(3/8));
is not running because of ln but I have changed to log. still an error of some operator.
x range of [1, 3]
y2 = (x-1)(log((3^.5)/2)*x-log(3/8));
plot(x,y2)
Thanks.

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回答（1 个）

Star Strider
Star Strider 2019-12-13
It is missing a multiplication operator:
y2 = (x-1)(log((3^.5)/2)*x-log(3/8));
↑
Try this:
y2 = (x-1).*(log((3^.5)/2).*x-log(3/8));
This also uses element-wise operations. See Array vs. Matrix Operations for an extended discussion.

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