Not enough input arguments?
显示 更早的评论
I'm trying to make a user-define function that accepts time as an input and gives me an output of height. Here is the code I am using currently.
For some reason it keeps giving me the error on line 2 that I do not have enough input arguments. What does this mean? Thank you!
function h=height(t)
h=(-(9.8/2).*t.^2)+(125.*t)+500;
end
采纳的回答
Image Analyst
2019-12-14
How are you calling it? What value are you passing in for t? You're not just clicking the green run triangle without giving it a value for t are you? So, let's say t was 10. Are you doing
t = 10;
h = height(t); % Pass in t to the height() function.
fprintf('For t = %.1f, height = %f.\n', t, h);
So, what is your program for calling your height() function? Evidently from the error it thinks you're doing this:
h = height(); % Not passing in anything for t. This will throw an error.
or else you're clicking the green run triangle which will try to run the function without sending in anything for t.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Platform and License 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
