How do I find the indices of the value of my matrix?

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Farshid Daryabor
Farshid Daryabor 2019-12-16
评论： Farshid Daryabor 2019-12-18
How can I find the indices and exactly position of the value of the attached file. For example find index of value = -69.19 from the attached file.
Thanks

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采纳的回答

Stephen23
Stephen23 2019-12-16
The answer depends entirely on how you define "equals" for floating point numbers:
>> [R,C] = find(abs(XX - -69.19)<1e-4)
R = []
C = []
>> [R,C] = find(abs(XX - -69.19)<1e-3)
R = 25
C = 124
>> [R,C] = find(abs(XX - -69.19)<1e-2)
R =
3
6
10
14
17
18
21
25
29
32
C =
108
110
113
116
118
119
121
124
127
129

更多回答（5 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2019-12-16
编辑：KALYAN ACHARJYA 2019-12-16
Load the mat file, say as data variable
idx=find(data==-69.19)
Please read about floating number precision (Must)
https://www.mathworks.com/help/matlab/matlab_prog/floating-point-numbers.html
Example:
>> A=[1 -69.19 3.5 10];
>> idx=find(A==-69.19)
idx =
2
Farshid Daryabor
Farshid Daryabor 2019-12-16
the commend tried before does not work,
idx=find(XX == -69.19);
idx = []
Farshid Daryabor
Farshid Daryabor 2019-12-16
I actually looking for an individual index (idx) for the corresponding value, as same for the latitude (idy). by the finding the indices I want to find a data as arranged based on the lon and lat,
data = var(idx,idy);
Farshid Daryabor
Farshid Daryabor 2019-12-16
Dear Stephen,
the second one is exactly what I am looking for. It's possible explaine why abs(XX - (-69.19)) should less than (1e-n), and how is defined 'n'
[R,C] = find(abs(XX - -69.19)<1e-3)
R = 25
C = 124
Farshid Daryabor
Farshid Daryabor 2019-12-16
the problem is when I want to find the certain variable from the matrix arranged based on the longitude and latitude, how can I find it by having the corresponding indices
Data=Data(y,x)

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