Error using nanstd function
显示 更早的评论
B=nanstd(X,0,'all');
when using the above statement in Matlab R2019a there are no problems, however when using it on another computer with R2017a, i get the error:
Error using size
Dimension argument must be a positive integer scalar within indexing range.
Error in var (line 109)
n = size(x,dim);
Error in nanvar (line 32)
y = var(varargin{:},'omitnan');
Error in nanstd (line 28)
y = sqrt(nanvar(varargin{:}));
采纳的回答
If you're computing the std over all elements of X, this works in any release.
B = std(X(~isnan(X)));
更多回答（1 个）
Steven Lord
2019-12-17
0 个投票
The ability to specify 'all' as a dimension in the var function (which the nanstd function calls) was introduced in release R2018b.
2 个评论
Adam Evenoff
2019-12-17
Steven Lord
2019-12-17
M = magic(5);
M(3, 3) = NaN;
std(M(:), 'omitnan')
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