How can I use legend for plotting dynamically sized matrix?
显示 更早的评论
I'm trying to plot a matrix that's returned from a function. The size of the matrix is 3xN, N is accepted with input. This is what I'm trying to get to work:
for i = 1:length(T(1,:))
plot(T(:,i));
legend([ num2str(i-1) '. Generation']);
end
but the legend is assigned only to the plot of the first column of the matrix for i's max value. Is it possible to get it to work properly? 
采纳的回答
Your loop is continuously overwriting the legend and only including the most recently plotted line. You actually don't need a loop at all.
T = randi(10,3,5); % fake data
plot(T)
legendStr = compose('%d Generation',(1:size(T,2))-1);
legend(legendStr)
If, for whatever reason, you prefer to produce the plot within a loop, here is the correct way to do that.
T = randi(10,3,5); % fake data
axes()
hold on
for i = 1:size(T,2)
plot(T(:,i),'DisplayName', sprintf('%d Generation',i-1));
end
legend() % no need for inputs since we used DisplayName
4 个评论
Emin Yilmaz
2019-12-18
Adam Danz
2019-12-18
You could do it in a loop as my 2nd example shows but it's best to use the non-loop method. So, good choice! For plot(T), if T is a matrix, a line will be created for each column in T.
Robin Amar
2021-9-3
编辑：Robin Amar
2021-9-3
Hello Adam,
As I had similar requirement, therefore, I tried your option 1 with my code.
But, I cannot see multiple entries in the Legend display.
My Code:
phi = linspace(-4*pi, 4*pi, 30);
legendStr = compose('Angle: %s', int2str(phi));
legend(legendStr);
The output is as seen below (only one entry for all the traces):
Actually, I expected the output to be something like (independent entry for every trace):
Any Suggestions...??
Adam Danz
2021-9-3
I only see one line in your plot so there's only going to be one legend entry per line.
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