Help keep getting error: Error using matlab.graphics.chart.primitive.Surface, Value must be a vector or 2D array of numeric type

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James Hull 2019-12-19

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https://ww2.mathworks.cn/matlabcentral/answers/497476-help-keep-getting-error-error-using-matlab-graphics-chart-primitive-surface-value-must-be-a-vector

评论： Kavya Vuriti 2020-3-31

在 MATLAB Online 中打开

I keep getting the following error:

Error using matlab.graphics.chart.primitive.Surface

Value must be a vector or 2D array of numeric type

I'm trying to mesh my second order regression results.

Thank you for any help!

figure(7)
scatter3(x1,x2,x3,y,'filled','k');
hold on
x1fit = linspace(min(x1),max(x1),30);
x2fit = linspace(min(x2),max(x2),100);
x3fit = linspace(min(x3),max(x3),100);
[X1FIT,X2FIT,X3FIT] = meshgrid(x1fit,x2fit,x3fit);
YFIT = -2166.2 + 509.5*X1FIT - 1.8*X2FIT + 56.52*X3FIT+3.02*X1FIT.*X3FIT-37.45*(X1FIT.^2)-2.14*(X3FIT.^2);
mesh(X1FIT,X2FIT,X3FIT,YFIT)
xlabel('Substrate')
ylabel('Temp')  
zlabel('Yield')
title('Multiple regression surface model')
s = surface;
c = s.CData;
s.CDataMapping = 'direct';
hold off

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Star Strider 2019-12-19

The problem is that ‘X!FIT’ and the rest are (30x100x100) 3D arrays.

Unfortunately, in this uinverse (with three large dimensions and time), it is only possible to represent three spatial dimensions and one time dimension. MATLAB follows that convention.

It may be possible to do what you want, however we need more details on what you calculated and what you want to plot.

Kavya Vuriti 2020-3-31

Hi,

Could you provide more inputs on what you want to achieve. The error is because meshgrid function in the above code is giving 3D arrays as output and these cannot be used as inputs to mesh function.

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