Creating an array from 1 to n

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Agnieszka Polak
Agnieszka Polak 2019-12-20
评论： Hans Henning Erle 2021-11-17
Hello!
I am trying to create an array of integers from 1 to n [1 2 3 ..... n], where n is a variable that can change.
How should I approach that?
Thank you!
  3 个评论
显示 1更早的评论
Luis Benitez Prieto
Luis Benitez Prieto 2021-7-27
It is elemantary but also not. If you look at the accepted answer below. The answer is creating a double array, the numbers inside are integer values, but not of interger format.
I actually was interested in this question because when I want to create an array of integers I do not want to create a double array in the process by doing something like:
uint32([1:10])
Instead, I would like to directly create an integer array. And thats something I have not easily found in the documentation and a legit question in my opinion. Perhaps thats what the poster is asking for.
Stephen23
Stephen23 2021-7-27
编辑：Stephen23 2021-7-27
Ran in:
@Luis Benitez Prieto: like this:
V = uint32(1):uint32(10)
V = 1×10
1 2 3 4 5 6 7 8 9 10
class(V)
ans = 'uint32'
Note that just one uint32 input is sufficient to define the output as uint32:
class(uint32(1):10)
ans = 'uint32'
class(1:uint32(10))
ans = 'uint32'
Note that the square brackets in your example are superfluous and misleading:
https://www.mathworks.com/matlabcentral/answers/35676-why-not-use-square-brackets

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采纳的回答

Alex Mcaulley
Alex Mcaulley 2019-12-20
n = 10 %
1:n
ans =
1 2 3 4 5 6 7 8 9 10
  2 个评论
Rui
Rui 2021-10-30
编辑：Rui 2021-10-30
how can i get it in reverse order also with a 0 in end?
like this
10 9 8 7 6 5 4 3 2 1 0

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