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How can I show a certain value in a certain position in the figure?

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Tania Islam 2019-12-26

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评论： Tania Islam 2019-12-30

采纳的回答： Mark Sherstan

Hello,

I want to a specific value in the figure. I put the black circle and arrow manually through the figure insert option. But How can I set the value now?

I want the x-axes values that are exactly 90% of each CDF curve.

here I am attaching my matlab figure in jpg mode.

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Mark Sherstan 2019-12-26

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在 MATLAB Online 中打开

Here is a quick example. If you do not have an equation you can still solve for the 0.9 value using numerical methods but the key is the text function.

% Some equation 
syms x
eq = 0.2*x;
% Solve for x coord 
S = vpasolve(eq == 0.9, x)
% Plot
fplot(eq)
% Add labels
hold on
plot(S, 0.9, 'o')
text(S, 0.9, string(S))
hold off

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Actually, I dont have any equation. I have only a long array from where I am counting my CDF and plot it.

I am sorry, I cannot understand your example perfectly.

Mark Sherstan 2019-12-26

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在 MATLAB Online 中打开

If you just have data use the interp1 function to find the x value that corresponds to your y value. So it would look something like this:

% X and y values for one data series
x = [...] 
y = [...] 
% Interpolate the x value for a y value of 0.9
xq = interp1(y,x,0.9)
% Plot the data
plot(x,y)
% Add a circle and text at the area of interest
hold on 
plot(xq, 0.9, 'o')
text(xq, 0.9, string(xq))
hold off

You may want to use a different interpolation method depending on how accurate you need the labels and how many data points you have. Read the documentation in the link I provided for more information.

Tania Islam 2019-12-27

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My_data.mat

Thank you so very much for your kind reply.

It works fine for the smaller dataset when I checked it. But when I am trying use in my dataset I am having problem. Like data must be unique. Problem is that in my dataset there is no specific point of 0.9. It may 0.980000012 this way. I am attaching here my dataset for your kind considerations.

I am sorry, I went to the link you provided. I can set the range but how can I get that point value which is very very close to 0.9?

Mark Sherstan 2019-12-27

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I dont fully understand your problem. Please post your code as I got an answer that made sense by just interpolating.

Tania Islam 2019-12-27

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Thank you..

Tania Islam 2019-12-27

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Test_code.m
figure.jpg

This is my code. I generalize my code. I store my original data output into the variabes, X1_axes, Y1_axes, X2_axes and Y_2axes.

Then I am plotting them in the figure. As I marked in the figure, I want to visulaize this data in my figure.

In your last code, it was perfectly work for small data.

Thank you for time and considerations.

Mark Sherstan 2019-12-27

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编辑：Mark Sherstan 2019-12-27

在 MATLAB Online 中打开

plot.png

Try this (I removed your data set, you just need to copy and paste it back in at the start):

% Find values of interest
xq1 = interp1(Y1_axes,X1_axes,0.9);
xq2 = interp1(Y2_axes,X2_axes,0.9);
% Make the main plot
figure('name','figure','NumberTitle','off');
plot(X1_axes, Y1_axes,'-r')
hold on
plot(X2_axes,Y2_axes,'-g')
hold off
% Add first marker
hold on
plot(xq1, 0.9, 'ko')
text(xq1, 0.85, num2str(xq1))
hold off
% Add secound marker
hold on
plot(xq2, 0.9, 'ko')
text(xq2, 0.95, num2str(xq2))
hold off
% Formatting 
xlabel('time error')
ylabel('CDF')
set(gca,'YTick',0:0.1:1)