Filling pie graph partitions without the Pie command

Question

Daniel 2019-12-26

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https://ww2.mathworks.cn/matlabcentral/answers/498116-filling-pie-graph-partitions-without-the-pie-command

回答： Chidvi Modala 2019-12-30

Hi everyone,

I have created a code which basically produces a pie graph between two rings, but I am stuck at filling my partitions with different colors. Does anyone have an Idea to how to solve this? I tried using patch and fill but I can't seem to get them to follow the circles (they just connect the endlines of the partition with a line, not following the circle)

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Sergey Kasyanov 2019-12-27

I will try to complete your code if you attache it or I will write my own code for plotiing a pie with filled sectors.

Daniel 2019-12-27

I have found a solution which does the job but isn't very nice. It's basically plotting a lot of fat lines to fill the circle.

Thanks anyways for the quick reply!

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Answer 1

Chidvi Modala 2019-12-30

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https://ww2.mathworks.cn/matlabcentral/answers/498116-filling-pie-graph-partitions-without-the-pie-command#answer_408150

在 MATLAB Online 中打开

You can make you of following code

function pie_chart
% Define quadrants and color
r1 = 1;                                                      % Outer radius
r = 0.5;                                                     % Inner radius
v = [5 15 25 20 35];
C = {'r' 'b' 'm' 'c' 'g'};
theta= 0:0.01:2*pi;
idx_spokes = round( [1 cumsum(v)/100*length(theta) ] ) ;     % find the indices of the spokes
for k=1:length(idx_spokes)-1
   t = theta( idx_spokes(k):idx_spokes(k+1) ) ;              % Theta for Inner ring
   si=theta( idx_spokes(k));                                 % Start index of polygon to be filled
   t1 = theta( idx_spokes(k+1):-1:idx_spokes(k) ) ;          % Theta for Outer ring
   x=[r*cos(t) r1*cos(t1) r*cos(si)];
   y=[r*sin(t) r1*sin(t1) r*sin(si)];
   plot(x,y);  
   hold on
   fill(x,y, C{k} );
end
axis square
axis on