Revised: find the frequency corresponding to max. magnitude in spectrum (FFT)

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Passband Modulation 2012-10-4

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采纳的回答： Wayne King

the spectrum of a message is shown as follows

where magnitude plot of the Fourier transform for message versus frequency in Hz is seen.

how can i find the dominant frequency with the use of the command max and command freqz?

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Answer 1

Wayne King 2012-10-4

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编辑：Wayne King 2012-10-4

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Why are you calling freqz() on the frequency response???

    [freq_resp,freq]=freqz(message,1,100000,22000);
    [maxval,index] = max(abs(freq_resp));
    freq(index)

I also question whether you should be using freqz(), That is really intended for filters where the inputs are the filter numerator and denominator coefficients.

Why not use the PSD

[Pxx,Fxx] = periodogram(message,rectwin(length(message)),length(message),22000);
[maxval,index] = max(Pxx);
Fxx(index)

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Passband Modulation 2012-10-4

编辑：Passband Modulation 2012-10-4

my course notes advise that freqz() might help but is not necessary. this is mentioned so because the question raised is actually related to "least squares filter" used for interference cancelling which is what i am working on now.

ur suggestion of PSD does help. it turns out the right result as the plot indicates. thx!!

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Answer 2

Wayne King 2012-10-4

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编辑：Wayne King 2012-10-4

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If you are using freqz(), freqz() returns the frequency vector, so just query the max value of the absolute value of the frequency response and then use that index to find the frequency.

   h = [1/sqrt(2) 1/sqrt(2)];
   [H,F] = freqz(h,1);
   [maxval,index] = max(abs(H));
   F(index)

This example gives 0, because h is a lowpass filter with the maximum at 0 radians/sample.

freqz() takes the sampling frequency as an input argument so that you can get the frequencies in Hz.

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Passband Modulation 2012-10-4

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thank again for your kind reply! the spectrum is plotted using

 [freq_resp,freq_index]=freqz(message,1,100000,22000);
  plot(freq_index,abs(freq_resp))

so i wonder how to commbine urs with the code shown above? will it be the following?

[freq_resp,freq_index]=freqz(message,1,100000,22000);
plot(freq_index,abs(freq_resp))
   [H,F] = freqz(freq_index,freq_resp));
   [maxval,index] = max(abs(H));
   F(index)

i didnt make it right, however. result turns out to be zero. so could u plz modify?

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