how do i write code for following equation

4 次查看(过去 30 天)
l=4
d=[10:10:100]*10^-6;
D=100*10^-12;
m=10^4;
t1=d^2/6*D ;
t=t1 + (i-1)*Tp;
I'm confusing about time t,what is the value of t and length of t,c(t) and s(t)

回答(2 个)

KALYAN ACHARJYA
KALYAN ACHARJYA 2020-1-2
编辑:KALYAN ACHARJYA 2020-1-2
l=4;
d=(10:10:100)*10^-6;
D=100*10^-12;
m=10^4;
t1=(d.^2)./(6*D);
Tp=? %% Define Tp
t=t1+(i-1)*Tp;
e1=(4*pi*D*t).^(3/2);
e2=-d.^2./(4*D.*t);
c_t=(m./e1).*exp(e2)
For summation s(t), please see here
  4 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2020-1-2
yes here t represents
t=t1+(i-1)*Tp;
Rest code with Tp
l=4;
d=(10:10:100)*10^-6;
D=100*10^-12;
m=10^4;
t1=(d.^2)./(6*D);
Tp=30;
t=t1+(i-1)*Tp;
e1=(4*pi*D*t).^(3/2);
e2=-d.^2./(4*D.*t);
c_t=(m./e1).*exp(e2) % This the result for c(t) as an array
AJIT KUMAR
AJIT KUMAR 2020-1-6
sorry to say that but i'm not satisfied with your answer.ok i'm giving the code if there is anything wrong plz suggest some correction.
Thank u
m = 10^6; D = 100*10^-12; d = [10*10^-6:10*10^-6:100*10^-6];
r = 10*10^-6; Tp = 30;
l = 4;b = 0;L = 10;c=[];
%s=zeros();
s_diff_sum_i=zeros();g_d=zeros();g_diff_sum=zeros();si=[];
%i =l+1:L+l ;
% syms j;
%
for k=1:length(d)
ts = (d(k).^2)./(6.*D);
ti=l*Tp:Tp:(L+l-1)*Tp ;
t1 = ts +ti; s3=0;
for j=0:4
c_temp = (m./(4.*pi.*D.*(t1+j*Tp )).^3/2).*exp(-(d(k).^2)./(4.*D.*(t1+j*Tp )));
c=[c c_temp];
s=sum(c_temp);
s1=sum(c);
s2=s2+c_temp;
end
s3(k)=s;
s4(k)=s1;
end

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AJIT KUMAR
AJIT KUMAR 2020-1-3
i have already written the code for these equation but i'm confused about output of t,s(t).if u don't mind please give me the output of t as well as s(t).i used "for loop" for t as well as for s(t).so tell me may i use "for loop "for t or not?.Any help is much appriciated.Thanks
  5 个评论
AJIT KUMAR
AJIT KUMAR 2020-1-6
m = 10^4; D = 100*10^-12; d = [10*10^-6:10*10^-6:100*10^-6];
r = 10*10^-6; Tp = 30;
l = 4;L = 10;c=[];
for k=1:length(d)
t1 = (d(k).^2)./(6.*D);
ti=l*Tp:Tp:(L+l-1)*Tp ; %%here i=l+1:L+l and ti=(i-1)*Tp
t= t1 +ti;
s3=0;
for j=0:4
c_temp = (m./(4.*pi.*D.*(t+j*Tp )).^3/2).*exp(-(d(k).^2)./(4.*D.*(t+j*Tp )));
c=[c c_temp];
s=sum(c_temp);
s1=sum(c);
s2=s2+c_temp;
end
s3(k)=s;
s4(k)=s1;
end
so,plz suggest me. should i use for loop for t and at final stage may i calculate sum(c) or sum(c_temp) .i shall be gratefull if u reply
Thank u
Walter Roberson
Walter Roberson 2020-1-6
I have no opinion on that matter, as I do not know what equations you are implementing. All I know is that you are not implementing the equations that were posted in your Question.

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