Vector multiplication for a vector with a transpose of vector i.e. one row vector and one column vector.

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altaf ahmed
altaf ahmed 2020-1-5
编辑： Matt J 2020-1-5
I am using this script to multiply two vectors as below:
%Parameters Declaration
S0T=[1,2,3,-1,-2]
S1T=[1,1,-2,2,-3]
S0=transpose(S0T)
S1=transpose(S1T)
S1=S0T*S0
S2=S0T*S1
S3=S1T*S0
S4=S1T*S1
But unfortunately I am not able to match the output with theoretical results as below:
Output:
S0T =
1 2 3 -1 -2
S1T =
1 1 -2 2 -3
S0 =
1
2
3
-1
-2
S1 =
1
1
-2
2
-3
S1 =
19
S2 =
19 38 57 -19 -38
S3 =
1
S4 =
19 19 -38 38 -57
>>
Theoretical Results:
S1=19 (This is correct)
S2=1 (This is Wrong as per Matlab results)
S3=1 (This is correct)
S4=19 (This is Wrong as per Matlab results)
Question: I want to know if there is a better commend/operator in MATLAB that can be used to multiply two vectors i.e. one row vector and one column vector.

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采纳的回答

Matt J
Matt J 2020-1-5
编辑：Matt J 2020-1-5
It's because you redefined S1 in line 6. Use distinct variable names for your outputs:
S0T=[1,2,3,-1,-2]
S1T=[1,1,-2,2,-3]
S0=transpose(S0T)
S1=transpose(S1T)
A=S0T*S0
B=S0T*S1
C=S1T*S0
D=S1T*S1
A =
19
B =
1
C =
1
D =
19

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