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the integer part of the division

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vaggelis vaggelakis
评论： Royi Avital 2021-4-9
hello everyone
how do i get the integer part of the output of a division i.e. 23/5=4 (and the remainder is 3)

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Azzi Abdelmalek
Azzi Abdelmalek 2012-10-4
编辑：Azzi Abdelmalek 2012-10-5
fix(23/5) % integer part
rem(23,5) % remainder
%or
mod(23,5)
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Royi Avital
Royi Avital 2021-4-9
It works only for Float64 and Float32.
For integer types use idivide.

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Walter Roberson
Walter Roberson 2012-10-5
Consider -23/5 (that is, the case of negative numbers.) Should that be -4 times 5 and remainder -3, or should it be -5 times 5 and remainder 2 ?
If you want the -4 version so that abs() of the "integer part" of -23/5 and 23/5 are the same, then use fix()
If you want the -5 version so that the remainder is always non-negative, then use floor()
You can use either fix() or floor() if you only have positive values, with floor() being preferred (more efficient, mathematically clearer)
Do not use round() even if you have only positive values. round(23/5) is 5, not 4.

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