the integer part of the division

1,020 次查看（过去 30 天）
vaggelis vaggelakis
评论： Royi Avital 2021-4-9
hello everyone
how do i get the integer part of the output of a division i.e. 23/5=4 (and the remainder is 3)

请先登录，再回答此问题。

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-10-4
编辑：Azzi Abdelmalek 2012-10-5
fix(23/5) % integer part
rem(23,5) % remainder
%or
mod(23,5)
  3 个评论
显示 1更早的评论
Royi Avital
Royi Avital 2021-4-9
It works only for Float64 and Float32.
For integer types use idivide.

请先登录，再进行评论。

更多回答（1 个）

Walter Roberson
Walter Roberson 2012-10-5
Consider -23/5 (that is, the case of negative numbers.) Should that be -4 times 5 and remainder -3, or should it be -5 times 5 and remainder 2 ?
If you want the -4 version so that abs() of the "integer part" of -23/5 and 23/5 are the same, then use fix()
If you want the -5 version so that the remainder is always non-negative, then use floor()
You can use either fix() or floor() if you only have positive values, with floor() being preferred (more efficient, mathematically clearer)
Do not use round() even if you have only positive values. round(23/5) is 5, not 4.

类别

在 Help Center 和 File Exchange 中查找有关 Direction of Arrival Estimation 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by