Solve the following system of non-linear equations

1 次查看（过去 30 天）
ahmed hone
ahmed hone 2020-1-7
编辑： Walter Roberson 2020-1-7
Solve the following system of non-linear equations:
xyz - x 2 + y 2 = 1.34
xy - z 2 = 0.09
ex - e y + z = 0.41
Use the initial values of (x0, y0, z0) = (0, -1, 0) and the termination criateria of 0.1% for the approximate error norm.

请先登录，再回答此问题。

回答（1 个）

Cameron B
Cameron B 2020-1-7
syms x y z
eqn1 = x*y*z - x^2 +y^2 - 1.34;
eqn2 = x*y - z^2 - 0.09;
eqn3 = exp(x) - exp(y) + z - 0.41;
sol = vpasolve(eqn1,eqn2,eqn3,[x,y,z],[0,-1,0]);
disp(sol.x)
disp(sol.y)
disp(sol.z)
  1 个评论
Walter Roberson
Walter Roberson 2020-1-7
编辑：Walter Roberson 2020-1-7
It seems likely to me that the question posed was a direct homework assignment, and you have just provided a complete solution without guiding the poster through learning the steps...
On the other hand, the bit about "termination criateria of 0.1% for the approximate error norm." tells me that the user was expected to write iterative numeric solutions, so your symbolic solution might not be all that useful for them.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Calculus 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by