Ascending table column labels

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Joost de Witte
Joost de Witte 2020-1-7
评论： Star Strider 2020-1-7
Hello all,
I've got a table which contains 38 column's, each representing one cycle. I want to label them "cycle 1", "cycle 2", etc.
I tried something like this, but this doesn't work. Any help would be appreciated, thank you!
colnames = "Cycle" + 1:size(matrix,2);
table = array2table(matrix,'VariableNames', colnames);

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采纳的回答

Star Strider
Star Strider 2020-1-7
Use the compose function (R2016b and later versions):
colnames = compose("Cycle %d", 1:size(matrix,2));
Alternatively, use the sprintfc (undocumented) function:
colnames = sprintfc("Cycle %d", 1:size(matrix,2));
No loop necessary.

更多回答（1 个）

Jesus Sanchez
Jesus Sanchez 2020-1-7
编辑：Jesus Sanchez 2020-1-7
I would do it inside a for loop:
matrix = [1 2 3; 3 4 5; 6 4 5; 9 8 7]; % 4 rows and 3 columns
colnames = {}; % Initializes colnames
for n=1:size(matrix,2)
colnames{end+1} = ['Cycle ' num2str(n)];
end
colnames = colnames.'; % To put them in one column, for readability
Result:
ans =
3×1 cell array
{'Cycle 1'}
{'Cycle 2'}
{'Cycle 3'}

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