How to do average of different arrays of a matrix?

2 次查看（过去 30 天）
AS
AS 2020-1-8
评论： AS 2020-1-8
I have a matrix having dimension 3490 by 63 and I want make it 698 by 63 by taking average of five data points of different row in a column. For single column my code is working but I want do the same for rest of 62 columns. please help me on this.
clc;clear all;close all;
load data1.dat;
X=data1;
X1=X(:,1)
n=1;
m=5;
sum=[ ] ;
fid1=fopen('smthdata1.dat','w');
for i=1:698;
sum=0;
for j1=n:m
sum=sum+X1(j1);
end
ad_n=(sum./5);
fprintf(fid1,'%d \n',ad_n);
n=m+1;
m=m+5;
i=i+1;
end
fclose(fid1);

请先登录，再回答此问题。

采纳的回答

Hiro Yoshino
Hiro Yoshino 2020-1-8
编辑：Hiro Yoshino 2020-1-8
Stephen Cobeldick is right.
Try this:
% X --> 3490 x 63 matrix
X = reshape(X, 5, 63, 698);
X = mean(X);
X = reshape(X, 698, 63);

更多回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2020-1-8
编辑：KALYAN ACHARJYA 2020-1-8
Yes, Stephen is rightly said, other options, array function or you can use this custom function for Block-wise Operations (5,1)
mat_data=rand(3490,63);
result=sepblockfun(mat_data,[5,1],'mean');

类别

在 Help Center 和 File Exchange 中查找有关 Statistics and Machine Learning Toolbox 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by