Anonymous function to calculate a sum

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Ellen De Jonghe 2020-1-9

评论： Stephen23 2020-1-9

Hye

I have to write an anonymous function which calculates the following sum for a given real number x and a positive integer:

x + (x^2)/2! + (x^4)/4! + ... + (x^2n)/(2n)!

I started off with this:

ch = @(x,n) ...

But I don't know how I can calculate the sum with only the anonymous function.

Stephen23 2020-1-9

编辑：Stephen23 2020-1-9

>> fun = @(x,n) x + sum(x.^(2:2:2*n) ./ factorial(2:2:2*n));
>> fun(3,5)
ans =  12.066

Compare against your expansion:

>> x = 3;
>> fun(x,2)
ans =  10.875
>> x + (x^2)/factorial(2) + (x^4)/factorial(4)
ans =  10.875

Stephen23 2020-1-9

Ellen De Jonghe's "Answer" moved here:

Thanks a lot!

Stephen23 2020-1-9

@Ellen De Jonghe: my pleasure! Please don't forget to accept my answer if it helped you.

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