Why delete(fin​dobj(gca,'​type', 'patch')) is not working for erasing scattered points ?

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JP Schnyder
JP Schnyder 2020-1-13
编辑： Adam Danz 2020-1-14
Here's a simple snippet that shows that
delete(findobj(gca,'type', 'patch'))
is not working for erasing scattered points:
figure
x = [1,2,3,4]
y = [1,2,3,7]
scatter(x,y,50);
delete(findobj(gca,'type', 'patch')) % not working
%delete(findobj(gca,'SizeData', 50)) % does work
Uncommenting the last line solves the problem, but this is a workaround, or what ?

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采纳的回答

Adam Danz
Adam Danz 2020-1-13
编辑：Adam Danz 2020-1-14
"Why delete(fin​dobj(gca,'​type', 'patch')) is not working for erasing scattered points ?"
Because s = scatter(___) produces a scatter object, not a patch object.
Instead,
delete(findobj(gca,'type', 'scatter'))
Or better yet, use the scatter output which does not require the use of the axis handle and is more responsible since you're deleting a specific object rather than deleting all existing matches to an object type within the current axes.
s = scatter(. . .);
delete(s)

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