vector not produced missing some '.' ?
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something is wrong with this code
t=0:0.1:1;
g = (0.30/(2*(pi*t^3)^0.5))*exp((-0.30^2)/(4*t));
As the vector g never gets made, I'm sure I need to put some '.' somewhere but I really don't understand this whole '.' stuff
1 个评论
Paulo Silva
2011-4-7
Sean answer is great for such cases, also when there's one dot missing matlab tells you what's the operation in the error message:
mtimes % before *
mdivide % before /
mpower % before ^
采纳的回答
Paulo Silva
2011-4-7
t=0:0.1:1;
g = (0.30./(2*(pi*t.^3).^0.5)).*exp((-0.30^2)./(4*t));
更多回答（3 个）
Sean de Wolski
2011-4-7
vectorize('g = (0.30/(2*(pi*t^3)^0.5))*exp((-0.30^2)/(4*t))');
A brainless way for us lazies.
4 个评论
Paulo Silva
2011-4-7
That's a good one, I must remember it :) +1 vote
but it too lazie, even for me lol
Matt Fig
2011-4-7
Even better(?) and definitely lazier.
eval(vectorize('g = (0.30/(2*(pi*t^3)^0.5))*exp((-0.30^2)/(4*t))'))
Paulo Silva
2011-4-7
... ..- .--. . .-. .-.. .- --.. .. .
Sean de Wolski
2011-4-7
Eval, is the king of MATLAB laziness!
Matt Fig
2011-4-7
As a general rule when dealing with operations on arrays, use a dot before every one of the three operators:
* / ^
If you do this you will be fine.
David Young
2011-4-7
If you don't understand the operators, the most straighforward thing is to use
g = (0.30 ./ (2 .* (pi .* t .^ 3) .^ 0.5)) .* exp((-0.30 .^ 2) ./ (4 .* t));
so that all the operators behave as elementwise operators (which I guess is what you want). If you understand the difference, you can omit some of the dots, but they do no harm.
It's not all that hard really: *, / and ^ carry out matrix operations (like matrix multiplication, as defined here), while .*, ./ and .^ operate point by point on the elements of the matrices.
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