Parameter calculation by using loops in ODE45
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For any initial values(Ofcourse with limits) I used it either excutes on the 4th iteration or it would be beyond the MAX iteration.
I am afraid something is wrong and I need a help.
zspan=[0,400];
v0mat = [1 0.05 1];
tol = 10^-4; % Treshold
MAX = 1000;
v2 = 0.4;
interval = [0.01 0.2]; % alpha interval
a = interval(1);
b = interval(2);
alpha = (a+b)/2;
zsol = {};
v1sol = {};
v2sol = {};
v3sol = {};
for k=1:size(v0mat,1)
v0=v0mat(k,:);
[z,v]=ode45(@(z,v)rhs(z,v,alpha),zspan,v0);
zsol{k}=z;
v1sol{k}=v(:,1);
v2sol{k}=v(:,2);
v3sol{k}=v(:,3);
end
iter = 1;
while(abs((v(:, 2)) - v2) > tol)
alpha= (a + b)/2;
[z,v]=ode45(@(z,v)rhs(z,v,alpha),interval,v0);
if(abs(v(:,2))-v2 > 0)
b = alpha;
else
a = alpha;
end
iter = iter + 1;
if(iter > MAX)
return;
end
end
for k=1:size(v0mat,1)
figure(1)
plot(v2sol{k},zsol{k},'g')
xlabel('Velocity,w')
ylabel('Height, z')
grid on
end
function parameters=rhs(z,v,alpha)
Nsqr = 0.001;
db= 2*alpha-(v(1).*v(3))./(2*v(2).^2);
dw= (v(3)./v(2))-(2*alpha*v(2)./v(1));
dgmark= -Nsqr-(2*alpha*v(3)./v(1));
parameters=[db;dw;dgmark];
end
16 个评论
darova
2020-1-16
It is unclear what are you trying to do here. Are you trying to check the last value?
if(abs(v(:,2))-v2 > 0)
Dereje
2020-1-16
darova
2020-1-16
What is condition that alpha depends on?
Dereje
2020-1-16
darova
2020-1-16
How do you understand this line? What does it mean to you
if(abs(v(:,2))-v2 > 0)
Dereje
2020-1-16
darova
2020-1-16
But v(:,2) has many values. Which one should be greater than v2
Dereje
2020-1-16
darova
2020-1-17
I believe it's a column
Walter Roberson
2020-1-17
There will be one row of v for every timepoint.
Dereje
2020-1-17
Star Strider
2020-1-17
@Dereje — Parameter Estimation for a System of Differential Equations might be informative. It is not possible to determine that from the posted code.
Walter Roberson
2020-1-17
It is a column with one row for each timepoint. That makes (abs(v(:,2))-v2 > 0) a vector result that might be true for some of the time entries but false for other times. Which one time do you need it to be true for? If you want to be testing for the last time then
if (abs(v(end,2))-v2 > 0)
Dereje
2020-1-17
Walter Roberson
2020-1-17
编辑:Walter Roberson
2020-1-17
In your context, timepoint is z value. Your ode45 call will process over z in zspan, producing one row for each of a number of z values. (abs(v(:,2))-v2 > 0) is a vector result that might be true for some of the z entries but false for other times. You need to decide which z the condition must hold for.
Dereje
2020-1-18
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