how to read complex file data to matrix

2020 1 17
2 个回答
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更新时间：2020 1 18
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0 个投票

I have a.txt file, with complex data. the format is
1.958138021e-02 0.64646110658609712285 + 0.093290941560866688653j
1.958139648e-02 0.32117256288141476928 - 0.061542254916540022058j
1.958141276e-02 -0.22359569118086644601 + 0.3585713533321416846j
1.958142904e-02 -0.22397218216792619261 + 0.082213621398327246803j
1.999960938e-02 0
1.999962565e-02 0
1.999964193e-02 0
1.999965820e-02 0
2.000000000e-02 0.10412797744247889731 + 0.0081123700776114041067j
There's space between + and -. how can I read this file into a matrix with seperated I part and Q part.
like
1.958138021e-02 0.64646110658609712285 0.093290941560866688653
...
1.999960938e-02 0 0
2.000000000e-02 0.10412797744247889731 0.0081123700776114041067

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 采纳的回答

per isakson
per isakson 2020-1-17

0 个投票

Following Walter's advise
%%
chr = fileread('a.txt');
%%
chr = strrep( chr, ' + ', '+' );
chr = strrep( chr, ' - ', '-' );
cac = textscan( chr, '%f%f' );
%%
M = cat( 2, cac{1}, real(cac{2}), imag(cac{2}) );
>> M(1:3,:)
ans =
0 0.10413 0.0081124
1.6276e-08 -0.04608 -0.073765
3.2552e-08 -0.038321 0.076231

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vincent lin
vincent lin 2020-1-17
编辑：per isakson 2020-1-18
thank you. This works and is fast. I find there's another code by reading line by line. It works but is very slow. Your method is faster
fid = fopen ('a.txt','r');
ii = 1;
while ~feof(fid)
acorrente(ii, :) = str2num(fgets(fid));
ii = ii + 1;
end
fclose(fid);
data = [real(acorrente(:,1)) real(acorrente(:,2)) imag(acorrente(:,2))];

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Walter Roberson
Walter Roberson 2020-1-17

0 个投票

Sometimes easiest is to read the file as a character vector, use regexp to remove the space around the sign of the imaginary part, and then textscan. textscan and other numeric formats can read complex values when there is no space.
Or read the file as string and regexp to change lines that do not end in j to append + 0j on them. With all lines having the same format you can easily textscan to extract real and imaginary separately.

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