HEEELP : Index in position 2 is invalid. Array indices must be positive integers or logical values. !!!! why???

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ezgi ünlü
ezgi ünlü 2020-1-17
回答： Steven Lord 2020-1-17
Hello, this is my code as you can see;
while i wrote the FOR part, matlab gives me this error. PLEASE HELP ME
opticaxis=[];
center=(length(y))/2;
for i=1:length(lambda)
opticaxis(i,:)=E_z(:,center,i)'/(max(E_z(:,center,i)));
end
mesh(x/(1e-6),lambda/(1e-6),opticaxis)
view(2)
colormap jet
ax = gca;
ax.YDir = 'normal'
title('GRIN with Plane Wave')
xlabel('x(um)')
ylabel('\lambda(um)')

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回答（2 个）

Steven Lord
Steven Lord 2020-1-17
center=(length(y))/2;
for i=1:length(lambda)
opticaxis(i,:)=E_z(:,center,i)'/(max(E_z(:,center,i)));
end
If y is a vector with an odd number of elements (as an example let's say y has 3 elements) you're asking for an element of E_z that doesn't exist (in the 3 element example, you're asking for elements in the 1.5th column of E_z.)
If y is not a vector, you probably shouldn't be using length. Use size and ask for the size of y in a specified dimension.
AdamG2013468
AdamG2013468 2020-1-17
Your for loop index is:
for i = 0:length(lambda)
Within your for loop you are attempting to create a new variable "opticaxis". You cannot define the opticaxis(0,:) point during the first index of your for loop. Try replacing your starting index value with a 1 insted of 0 (example below). This may not solve your problem just yet, but should get you closer. Also, what is the value of length(lambda)?
for i = 1:length(lambda)
  1 个评论
ezgi ünlü
ezgi ünlü 2020-1-17
编辑：ezgi ünlü 2020-1-17
hello, thanks for your answer, i already write for i = 1:length(lambda) but yes, it is not solve my problem as you said. lambda is variant number, not constant about between 2.5 and 5. lambda is defined in the file.

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