Limiting mouseclick event to current Axes in App Designer

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Jason
Jason 2020-1-18
评论： Jason 2020-1-23
Hi, I am trying to get the mouselocation on an axes - 'app.UIAxes' (using app designer).
delete(findobj(app.UIAxes, 'Marker', '*')); %DElete previous marker
z=app.UIAxes.CurrentPoint;
x=z(1,1); y=z(1,2);
hold(app.UIAxes,'on');
plot(app.UIAxes,x,y,'b*');
hold(app.UIAxes,'off');
app.xy=[x,y]; %Save value so can access later
However, as I also have 2 other UIAxes (app.UIAxes2 & app.UIAxes3), whenever I click on any of them, it invokes the fucntion above and plots a point on the UIAxes.
How can I limit this to just the UIAxes
  2 个评论
J. Alex Lee
J. Alex Lee 2020-1-18
Can you show how you are defining the event callback function? Are you using the figure's windowbuttondownfcn?

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采纳的回答

Cameron B
Cameron B 2020-1-18
Find the pixel locations where you want the function to activate. If it’s a rectangle, then that’s easier. You’ll have four points - two x and two y. At the very beginning of your function you can write something like this:
function yourclickfunction
%cursorpos is going to be your current cursor position as (x,y)
%pos1 is your top right most point in your designated rectangle window as an (x,y)
%pos2 is is the bottom left most position in your designated rectangle window as an (x,y)
%you’ll have to determine pos1 and pos2 based on where you want your window clicks to run the function
if cursorpos(1) > pos1(1) || cursorpos(1) < pos2(1) || cursorpos(2) > pos1(2) || cursorpos(2) < pos2(2)
return
end
%run the rest of your code
end
  6 个评论
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Jason
Jason 2020-1-20
Cameron, your idea of:
function yourclickfunction
%cursorpos is going to be your current cursor position as (x,y)
%pos1 is your top right most point in your designated rectangle window as an (x,y)
%pos2 is is the bottom left most position in your designated rectangle window as an (x,y)
%you’ll have to determine pos1 and pos2 based on where you want your window clicks to run the function
if cursorpos(1) > pos1(1) || cursorpos(1) < pos2(1) || cursorpos(2) > pos1(2) || cursorpos(2) < pos2(2)
return
end
%run the rest of your code
end
doesnt seem to work. For example the x positon returned from cursorpos(1) seems to be with repect to the axes its in i.e. not global.
Jason
Jason 2020-1-23
Needed to use this:
if x >= app.UIAxes.XLim(1) & x <= app.UIAxes.XLim(2) & y >= app.UIAxes.YLim(1) & y <= app.UIAxes.YLim(2)

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更多回答（1 个）

J. Alex Lee
J. Alex Lee 2020-1-22
Cameron's idea of calculating the axes position within the figure position should work, and it is the only way with currently documented/supported matlab that I can think of too, though it would be nice if someone else could chime in.
The solution of extracting the actual axes object from the uiaxes is along the lines of what I would have suggested. But rather than create a uiaxes and get the axes from within, you can also create regular axes() inside a uifigure, and it will behave as usual (I haven't tested exhaustively, but it seems to be more or less interchangeable, except for behavior on resizing).
  1. In app designer, create a uipanel to be the container of the axes (because within appdesigner gui edtor you can't add an axes, only uiaxes), call it for example "AxesContainerPanel"
  2. In the code editor add a property called "UIAxes" (or whatever you want to call it)
  3. In the code editor add a startup function for the app
  4. In the startup function, create the axes:
app.UIAxes = axes(app.AxesContainerPanel,"ButtonDownFcn",@(o,e)AxesBDF(app,o,e))
  1 个评论
Jason
Jason 2020-1-23
So I got the idea from Cameron to work but changed the if condition to below:
z=app.UIAxes.CurrentPoint;
x=round(z(1,1)); y=round(z(1,2));
if x >= app.UIAxes.XLim(1) & x <= app.UIAxes.XLim(2) & y >= app.UIAxes.YLim(1) & y <= app.UIAxes.YLim(2)

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