Why I got the error "Undefined operator '.*' for input arguments of type 'function_handle"?

Question

Aimi Oguri 2020-1-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/500976-why-i-got-the-error-undefined-operator-for-input-arguments-of-type-function_handle

回答： Steven Lord 2020-1-19

RCac = @(~,state) (-k4.*(state.u(1)./K3+state.u(1)).^2+...
    k3.*state.u(1)./(KCICR+state.u).*(IP3./(IP3+K2)).^3.*Cas)...
    -kon.*state.u(1).*(BT-CaB)+koff.*CaB;
s = @(x, y) RCac;
Fe = wOmega(1) * PhiIPS(:, 1) .* s(ip(1, 1), ip(1, 2)) * areaOfElement + ...
         wOmega(2) * PhiIPS(:, 2) .* s(ip(2, 1), ip(2, 2)) * areaOfElement + ...
         wOmega(3) * PhiIPS(:, 3) .* s(ip(3, 1), ip(3, 2)) * areaOfElement;

I keep receiving the error message:

     'function_handle' 型の入力引数の演算子 '.*' が未定義です。
エラー: BarbeeModel (line 159)
    Fe = wOmega(1) * PhiIPS(:, 1) .* s(ip(1, 1), ip(1, 2)) * areaOfElement + ...

in English:

Undefined operator '.*' for input arguments of type 'function_handle'.
Error in
Fe = wOmega(1) * PhiIPS(:, 1) .* s(ip(1, 1), ip(1, 2)) * areaOfElement + ...

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Answer 1

Steven Lord 2020-1-19

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/500976-why-i-got-the-error-undefined-operator-for-input-arguments-of-type-function_handle#answer_410887

You can't multiply a function handle, which is what s returns. If you intend s to evaluate the function handle RCac, just make it an alias of that function handle.

s = RCac;

Or if you wanted to make it explicit in that line of code that s is a function handle:

s = @(x, y) RCac(x, y);

In either of these cases s(something, somethingElse) returns a number rather than a function handle, and you can multiply a number by another number.