Calc of mean and standard deviation
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Hi. I have
A = [1,-1,0,6,8,9]
B = [1,-2,0,-6,8,9]
C = [-2,-1,0,6,8,9]
How can I calc the mean of three of them (excluding NaN) std and plot them in one graph?
The result should look like the photo. Maybe this is elementary question but I'm still learning. Thanks.
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采纳的回答
Image Analyst
2020-1-23
Is this what you want:
A = [1,-1,0,6,8,9]
B = [1,-2,0,-6,8,9]
C = [-2,-1,0,6,8,9]
% Compute mean and std dev.
meanVec = mean([A; B; C], 'omitnan')
stdVec = std([A; B; C], 'omitnan')
% Plot everything
plot(A, 'r.-', 'LineWidth', 2, 'MarkerSize', 10);
hold on;
plot(B, 'g.-', 'LineWidth', 2, 'MarkerSize', 10);
plot(C, 'b.-', 'LineWidth', 2, 'MarkerSize', 10);
plot(meanVec, 'k.-', 'LineWidth', 2, 'MarkerSize', 10);
grid on;
legend('A', 'B', 'C', 'Mean', 'Location', 'northwest');
2 个评论
Image Analyst
2020-1-24
It's trivial to add it, and I expect you have already.
A = [1,-1,0,6,8,9]
B = [1,-2,0,-6,8,9]
C = [-2,-1,0,6,8,9]
% Compute mean and std dev.
meanVec = mean([A; B; C], 'omitnan')
stdVec = std([A; B; C], 'omitnan')
% Plot everything
plot(A, 'r.-', 'LineWidth', 2, 'MarkerSize', 10);
hold on;
plot(B, 'g.-', 'LineWidth', 2, 'MarkerSize', 10);
plot(C, 'b.-', 'LineWidth', 2, 'MarkerSize', 10);
plot(meanVec, 'k.-', 'LineWidth', 2, 'MarkerSize', 10);
plot(stdVec, 'm.-', 'LineWidth', 2, 'MarkerSize', 10);
grid on;
legend('A', 'B', 'C', 'Mean', 'Standard Deviation', 'Location', 'northwest');
更多回答(1 个)
John D'Errico
2020-1-23
编辑:John D'Errico
2020-1-23
It should look like what photo? The mind reading toolbox has never gotten past beta testing state, and the copy I have is full of bugs.
Hint: create ONE matrix, that is 3x6. Now can you use the functions mean and std on the matrix?
This points out the flaw in creating multiple variables, when one array will suffice.
3 个评论
John D'Errico
2020-1-23
编辑:John D'Errico
2020-1-23
Please stop answering with something that is purely a comment. You never even attached a picture to your answer. You clearly know how to make a comment, since you made one. And you can attach a picture to a comment.
But if you even admit a matrix would be helpful, then TRY IT!!!!!!! Make some effort.
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