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can't get all the other characters = 26

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Benjamin Trivers
Benjamin Trivers 2020-1-26
关闭： MATLAB Answer Bot 2021-8-20
Write a function m-file called stringcode that takes a string as input and produces an array containing a code for each letter in the string with A = 0, B = 1, ..., Z = 25 and all other characters getting the value 26.
function num = stringcode( word )
asc= double((word))
if asc >= 33 & asc <=47
asc = 26
else asc= double(upper(word))
end
asc= double(upper(word))
num = asc - double('A'); % simple arithmetic
end
  2 个评论
James Tursa
James Tursa 2020-1-26
asc is a vector, but your code treats it as a scalar. You either need to wrap your code in a loop to do each character one at a time, or you need to vectorize your code.

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回答（1 个）

Image Analyst
Image Analyst 2020-1-26
You don't need all that complicated stuff. You almost had it at the end, so simply subtract 'A' and you're done. None of that foregoing stuff is needed. Watch:
>> num = 'ABCDEFGHIJKLMNOP' - 'A'
num =
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
  2 个评论
Benjamin Trivers
Benjamin Trivers 2020-1-26
I still don't follow. Where does the num= go into?
Image Analyst
Image Analyst 2020-1-26
In your function of course:
function num = stringcode( word )
num = word - 'A'
num(num<0 | num>25) = 26;
Just throw out all that useless stuff you had and have just those three lines. Basically the same as what you have except you don't need to cast to double

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