converting string code into numbers?
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Write a function m-file called stringcode that takes a string as input and produces an array containing a code for each letter in the string with A = 0, B = 1, ..., Z = 25 and all other characters getting the value 26
Hints
- Convert the string to all upper case (using the command upper).
- Convert the string to an array of ascii codes (use double).
- Loop through the array and change the codes to the right values. Look up the codes for ’A’ and ’Z’.
here is my code
function num = stringcode( word )
asc = double(upper(word))
if asc >= 33 & asc <=47 & asc < 0
asc = 26
else asc = double(upper(word))
end
% simple arithmetic
num = asc - double('A')
end
I cant get the special characters to come up as the number 26
4 个评论
Walter Roberson
2020-1-26
Your input is a vector. asc is a vector. Your if is testing a vector. When you test a vector in if then it is only true if every value is true (non-zero).
Also there are no values that are both in the range 33 to 47 and less than 0 simultaneously.
Mohammad Sami
2020-1-28
编辑：Mohammad Sami
2020-1-28
Why don't you do this
num = double(upper(asc)- 'A') ;
num(num <0 || num > 25) = 26;
Walter Roberson
2020-1-28
The homework requires that a loop be used.
Rik
2020-1-28
Also, you need to use a single pipe character for an array, so that second line doesn't work.
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2020-1-26
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2021-8-20
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