plot graph for nested if
1 次查看(过去 30 天)
显示 更早的评论
l=input('l=');
for t=0:100
if t>2
g=((3/(309*0.0014))*((((0.0000126*(t-2))/l)*80.4)-(l/6)));
elseif t>80
g=l-((80.4/309)*exp(((((-3*0.0000126)/(0.0014*l))*(t-80)))));
else
g=0;
end
disp (g);
end
t=0:100;
plot (t,g)
can someone explain how to plot graph using this coding because the don't get the graph.
采纳的回答
Bhaskar R
2020-1-27
l=input('l=');
g = zeros(1, length(0:100));% initialize g with 0's of length t
c = 1; % counter variable
for t=0:100
if t>2
g(c)=((3/(309*0.0014))*((((0.0000126*(t-2))/l)*80.4)-(l/6)));
elseif t>80
g(c)=l-((80.4/309)*exp(((((-3*0.0000126)/(0.0014*l))*(t-80)))));
else
g(c)=0;
end
c = c+1; % increment counter variable
disp (g);
end
t=0:100;
plot (t,g)
7 个评论
Walter Roberson
2020-1-28
for t=0:100
t is a scalar
if (t(d)>2) && (t(d)<=80)
d is undefined. If d does not happen to be 1, then because t is a scalar, t(d) would be out of range.
for l=0.0002:0.001
every iteration of that loop, every different value of l, you are ovewriting all of g. The result would be the same as if you had only done the last of them, 0.0002 .
Notice by the way that because the default increment is 1, your code
for l=0.0002:0.001
is the same as
for l=0.0002 : 1 : 0.001
so 0.0002 would be used, then 0.0002+1 would be examined and found to be greater than 0.001 so the loop would stop.
更多回答(1 个)
Walter Roberson
2020-1-27
编辑:Walter Roberson
2020-1-27
l = input('l=');
t = 0:100;
g = zeros(size(t));
mask = t>2 & t <= 80
g(mask) = ((3/(309*0.0014))*((((0.0000126*(t(mask)-2))/l)*80.4)-(l/6)));
mask = t>80;
g(mask) = l-((80.4/309)*exp(((((-3*0.0000126)/(0.0014*l))*(t(mask)-80)))));
plot (t,g)
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!