loop to work with the column
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Hello! There is a loop, I need to know automatically how many values after the point
X=[1 2 3 4 5 6 90 70 60 50 6 5 4 3 2
1 2 3 4 5 6 60 70 60 50 6 5 4 3 2
1 2 3 4 5 6 60 60 70 50 6 5 4 3 2]';
for i=1:length(X(1,:))
[~,loc1]=max(X);
end
% and now I need to find out how many values from maxim to 6
% ans(1) = 4 % 70 60 50 6 % ans(2)=3 % 60 50 6 % ans(3)=2
how do i do this?
2 个评论
Stephen23
2020-1-27
"how many values after the point"
What exactly is "the point" ?
What is that loop supposed to do?
Lev Mihailov
2020-1-27
编辑：Lev Mihailov
2020-1-27
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此问题已关闭。
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2020-1-27
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2021-8-20
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