Need to match Data

1 次查看(过去 30 天)
Johannes
Johannes 2012-10-8
Hello,
I like to match the entries in column 2 of matrix A to the reference numbers of B. I'm going to do that for large data sets. Code like follows does exactly what I want but will be to slow. Is there an intelligent function/way available to do that? Thanks a lot!
A = [2 3 5 7; 23 54 76 86]';
B = [1:7]';
j=1;
for i = 1:7
if B(i,1) == A(j,1)
B(i,2) = A(j,2);
j = j+1;
end
end
result: B =
1 0
2 23
3 54
4 0
5 76
6 0
7 86

采纳的回答

Matt Fig
Matt Fig 2012-10-8
B(A(:,1),2) = A(:,2)
  2 个评论
Matt Fig
Matt Fig 2012-10-8
Johannes comments:
"Thank you. That was a bad example, my mistake.
What would be the solution for vectors like that:
A = [7 3 5 9; 23 54 76 86]';
B = [3:15]';"
Matt Fig
Matt Fig 2012-10-8
编辑:Matt Fig 2012-10-8
In that case:
A = [7 3 5 9; 23 54 76 86]';
B = [3:15]';
As = sortrows(A,1);
idx = ismember(B,As(:,1));
B(idx,2) = As(:,2)

请先登录,再进行评论。

更多回答(2 个)

Andrei Bobrov
Andrei Bobrov 2012-10-8
编辑:Andrei Bobrov 2012-10-8
A = [7 3 5 9; 23 54 76 86]';
B = [3:15]';
[a,b] = ismember(B,A(:,1));
B(a,2) = A(b(a),2);

Johannes
Johannes 2012-10-9
thank you all! My final solution is the following:
B(ismember(A),2)=A(ismember(A,B),2);
Works perfect and very fast.
Thank you again for your help.
Best, Johannes

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by