How to find min and its index in calendarDuration array

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Bohdan Perviy
Bohdan Perviy 2020-1-29
评论： Bohdan Perviy 2020-1-29
I got such an array and its min element has 8th index (the closest duraion). Min() function won't work. Apparently it needs some conversion
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Bohdan Perviy
Bohdan Perviy 2020-1-29
I moved back to the Duration class, because previously i used between() so that as a result i got calendarDuration array, but now i solved the problem using difference between Datetime array and Datetime value
% v1 = between(start_manvr, string(outcome(:,3)));
v1 = datetime(string(outcome(:,3))) - start_manvr
[c,index] = min(abs(v1));
Anyway, thanks for the tip about Duration class

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