How to replace a rectangle with another rectangle?

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Kirsten Moons
Kirsten Moons 2020-1-29
编辑： Ridwan Alam 2020-1-30
(Or change the properties of the first rectangle)
I had 2 ideas of how to replace the rectangle, but both don't work. But here they are:
Idea 1:
r = findobj('FaceColor', [0.2 0.2 0.7])
r.FaceColor = [0.2 0.2 0.2]
Idea 2:
r = rectangle(findobj('FaceColor', [0.2 0.2 0.7]))
r.FaceColor = [0.2 0.2 0.2]
Idea 3:
r = findobj('FaceColor', [0.2 0.2 0.7])
rectangle('Position',r.Position,'LineWidth',1, 'FaceColor', [0.2 0.2 0.7])
I think you can't story a rectangle in a variable but I'm not sure and don't know how to do it otherwise. I want to change the facecolor of the rectangle with the facecolor [0.2 0.2 0.7].
  2 个评论
Walter Roberson
Walter Roberson 2020-1-30
The form in Idea 1 worked when I tried it, if the goal is to change the color of an existing rectangle without creating a new one.
Kirsten Moons
Kirsten Moons 2020-1-30
Okay, thank you for your feedback. Then I don't know why it doesn't work for me.

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回答（1 个）

Ridwan Alam
Ridwan Alam 2020-1-30
编辑：Ridwan Alam 2020-1-30
I tried this, it worked for me:
r = rectangle('FaceColor', [0.2 0.2 0.7]);
r.FaceColor = [0.2 0.2 0.2];
  2 个评论
Kirsten Moons
Kirsten Moons 2020-1-30
I dont know the position of the rectangle, thats why I use findobj.
Ridwan Alam
Ridwan Alam 2020-1-30
编辑：Ridwan Alam 2020-1-30
Even this worked:
r = rectangle('FaceColor', [0.2 0.2 0.7]); % created the rectangle
r1 = findobj('FaceColor', [0.2 0.2 0.7]); % finds the rectangle handle
r1.FaceColor = [0.2 0.2 0.2]; % change rectangle property using handle
Please let me know which part is not working for you.
Btw, if the rectangle doesn't exist, findobj() returns an empty handle.

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