calculating mean values of a 3D matrix

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noa 2012-10-9

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评论： ankit patel 2020-4-11

采纳的回答： Andrei Bobrov

hi.

I have a 3D matrix. size 79x63x100

I want to calc the mean of each of the 79x63 values so to get a 2D matrix the size of 79x63x1

but when i do mean(mat) i get it in the size of 1x63x100

how should I write it?

Thanks, Noa

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Deepak Singh 2015-7-15

You can mention the dimension you want to take mean across. Something like this will work: x=mean(mat,3);

ankit patel 2020-4-11

its not working if i change the value 3 with more than 3 in your equation.

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采纳的回答

Andrei Bobrov 2012-10-9

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在 MATLAB Online 中打开

out = mean(yourarray3D,3)

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Akshay Bhardwaj 2018-5-24

编辑：Akshay Bhardwaj 2018-5-24

在 MATLAB Online 中打开

out = std(yourarray3d,[],3)

BBB 2019-11-13

在 MATLAB Online 中打开

Hi,

I also have a similar question.

I have a 51x51 2D matrix that I need to take a mean off, but it has to give me back a 51x51 2D matrix as an output.

How can do this using the mean function. I need to put this in a loop as well. Please see code below for reference:

rand_image_stim = rand(10000,51,51);
kk = 1:length(rand_image_stim);
firing_rate_kk(kk) = 0;
gab_filt = z_cos.*z_gauss;
lp(kk) = 0;
for kk = 1:length(rand_image_stim)
    output_kk = squeeze(rand_image_stim(kk,:,:)).*gab_filt;
    firing_rate_kk(kk) = sum(output_kk,'all');
    jk = squeeze(rand_image_stim(kk,:,:))*firing_rate_kk(kk);
    lp = squeeze(mean(jk,2)); %Need help with this last bit!
end

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MATLAB Language Fundamentals Matrices and Arrays Creating and Concatenating Matrices

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