Replace cell array based on condition

5 次查看（过去 30 天）
Song JL
Song JL 2020-2-2
评论： Song JL 2020-2-3
i have a problem in replacing cell array based on condition
if i have
A = {[1,1,2; 2,2,3];[1,3,4; 9,6,8];[1,2,5; 2,3,4];[1,1,4; 3,4,5]};
B = [2,2,2; 3,3,3];
then, the condition that apply is when A has a value more than 5 it should be replace with B
so, the result have to be like this
result = {[1,1,2; 2,2,3];[2,2,2; 3,3,3];[1,2,5; 2,3,4];[1,1,4; 3,4,5]};
is it possible to do that ?
Thanks in advance

请先登录，再回答此问题。

采纳的回答

Ioannis Andreou
Ioannis Andreou 2020-2-2
Use cellfun:
tfReplace = cellfun(@(c) any(any(c>5)), A, 'UniformOutput', true);
A{tfReplace} = B;
  2 个评论
Song JL
Song JL 2020-2-3
Hi, what if i have more than one array that need to be replaced??
for example:
A = {[1,1,2; 2,2,3];[1,3,4; 9,6,8];[1,7,8; 2,3,4];[1,1,4; 8,6,5]};
and then the result should be
result = {[1,1,2; 2,2,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3]};
i have tried to solve it using for , but i still get an error
here is my code
for r = 1:length(tfReplace)
A{tfReplace(r)} = B;
end
seems that it isn't appropriate way..

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by