Replace multiple matrix in a cell array based on condition
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need a help in replacing matrix in cell array
if i have cell array and matrix like this
A = {[1,1,2; 2,2,3];[1,3,4; 9,6,8];[1,7,8; 2,3,4];[1,1,4; 8,6,5]};
B = [2,2,2; 3,3,3];
when A has a value more than 5, it should be replace with B
then, the result have to be like this
result = {[1,1,2; 2,2,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3]};
i have tried this, but it still gives me an error
rep = cellfun(@(c) any(any(c>5)), A, 'UniformOutput', true);
A{rep} = B;
Expected one output from a curly brace or dot indexing expression, but there were 2 results.
Any idea ?
Thanks in advance..
采纳的回答
You were almost there, just one small change is required:
To assign to an unknown number of LHS elements the RHS must be scalar. In your case you want to assign cells themselves so the simplest is to make the RHS one scalar cell (not a non-scalar numeric).
>> idx = cellfun(@(c) any(c(:)>5), A); % default UniformOutput = True
>> A(idx) = {B}; % unknown number of cells = scalar cell
>> A{:}
ans =
1 1 2
2 2 3
ans =
2 2 2
3 3 3
ans =
2 2 2
3 3 3
ans =
2 2 2
3 3 3
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