how to replace missing values from a double inside a cell array?
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I really thanks in advance anybody can tell me how can I replace THE missing values (100000) in the below cell array with NaN.
A = {[1,2,3,100000,4,5,100000],[6,100000,7,100000]};
采纳的回答
JESUS DAVID ARIZA ROYETH
2020-2-5
newA=cellfun(@(x) x.*(x~=100000)./(x~=100000),A,'Uni',false)
更多回答（1 个）
index=find(A==100000); %found 100000 in the A
A(index)=NaN; % Replace them by NaN
2 个评论
JESUS DAVID ARIZA ROYETH
2020-2-5
'==' does not work with argument of type cell
BN
2020-2-5
Dear JESUS,
You are right, It's my bad. Thank you for letting me know
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