I have a matrix that is 17x6 and for one task i need to find • The location with the highest average ice thickness • The maximum overall ice thickness measurement with the associated location and day

Question

Alex Doan 2020-2-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/503927-i-have-a-matrix-that-is-17x6-and-for-one-task-i-need-to-find-the-location-with-the-highest-average

回答： Jyothis Gireesh 2020-2-10

MA2_data (2).mat

I'm confused on how to do this. more so on how to get the index the day and location. But the location name is on a 1x6 and we have to index the name and also the Days is on a 17x1. use the data and scrool down to the bottom to get an idea of how it should look

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Jyothis Gireesh 2020-2-10

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/503927-i-have-a-matrix-that-is-17x6-and-for-one-task-i-need-to-find-the-location-with-the-highest-average#answer_414743

在 MATLAB Online 中打开

I am assuming here that the rows of the “Ice” matrix correspond to the “Days” and the columns correspond to the “LocationID” . You may use the following code to extract the required values.

clear; 
load('MA2_data (2).mat');
[~, maxAvgIceLocation] = max(mean(Ice(:)));
maxIce = max(Ice(:));
[maxRow, maxCol] = find(ismember(Ice, maxIce));
maxDay = Days(maxRow);
maxLocation = LocationID(maxCol);

Here the variable “maxAvgIceLocation” correspond to the location of the highest average ice thickness. “maxIce”, “maxDay”and “maxLocation” gives the maximum overall ice thickness with the associated day and location respectively.