How to simplify the loops of a matrix
1 次查看(过去 30 天)
显示 更早的评论
Hello. I have an issue with a code performing some calculations in two loops . It is very slow since I am using two loops. Could you please help me solve this,
Clear all
nx = 100;
ny = 200;
phi = random(nx,ny);
num = 5;
phi1 =zeros(nx,ny);
for i =1:nx
for j = 1:ny
phi1 = mod(phi(i,j), num);
end
end
figure(1)
surf(phi1)
0 个评论
采纳的回答
Robert U
2020-2-6
Hi Xinyuan,
the code snippet you are providing does not make any use of the two for-loops. You can remove them, since the function mod() is applied to each element of the matrix "phi". The result is the same. Your code just overwrites the same matrix for nx x ny times.
clear all
nx = 100;
ny = 200;
phi = rand(nx,ny);
num = 5;
phi1 = mod(phi, num);
figure
surf(phi1)
Kind regards,
Robert
4 个评论
Robert U
2020-2-6
Hi Xinyuan,
your introduced change illustrates the problem that you solved partially yourself posting the former code snippet:
Remove the two for-loops and the indexing. The function mod() performs the modulo-operator on each single element of the matrix phi, thus there is no loop necessary.
Kind regards,
Robert
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!