Error with find function in a for loop
显示 更早的评论
Time, height, and temperature variable all have the same array size. I want find temperature at altitude greater than 6km. I also want 6kmtemp to be the same size as temperature. However, after running this code, the result was an empty array. t3 is 0*0. How can I make this find function work in a for loop. BTW, the find function worked when i didnt have it in the loop. However, the array size changed. What am i missing? Thanks
for i=1:length(Time)
t3=find(height(i)>=6);
6kmtemp(i,t3)=temperature(t3);
end
2 个评论
Star Strider
2020-2-6
Note that:
6kmtemp
is not an acceptable variable name, and will throw an error.
Consider:
temp6km
instead.
Kafayat Olayinka
2020-2-6
采纳的回答
TADA
2020-2-6
Find accepts a logical vector and returns all the indices containing 1.
The problem is you are giving find a scalar value so it's going to return an empty value when height(i) < 6 and 1 whenever height(i) >= 6
Did you consider not using find at all? Instead you can switch to logical indexing:
6kmtemp = nan(size(temperature));
atLeast6km = height >= 6;
6kmtemp(atLeast6km) = temperature(atLeast6km);
You should preallocate 6kmtemp to whatever value you want the "empty" cells to have, I used NaN but you can define your own constants according to what makes sense for you
4 个评论
TADA
2020-2-6
I'm pretty confident you have to use an English letter as the first character of a variable name though... Does it let you define a variable named 6kmtemp?
Kafayat Olayinka
2020-2-6
Kafayat Olayinka
2020-2-6
TADA
2020-2-6
Cheers
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
