finding nonzero elements in matrix
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Hello,
I have a matrix with the values of either zero or one; I want to find non zero elements in every coloumn and locate the indices of each non zero element in every coloumn of a new matrix. For example, let's say my original matrix looks like this:
a =
0 1 1
0 0 1
1 1 1
I want the indices of non zero element in a new matrix look like this:
b =
0 1 1
0 0 2
3 3 3
How can I do it? I tried with the find function but without any success.
Thanks in advance,
Tilek
采纳的回答
iwant = zeros(size(A)) ;
for i = 1:size(A,1)
if any(A(i,:))
iwant(i,A(i,:)~=0) = i ;
end
end
更多回答（1 个）
Steven Lord
2020-2-10
Use implicit expansion.
A = [0 1 1; 0 0 1; 1 1 1];
R = (1:size(A, 1)).';
B = A.*R
3 个评论
Tilek Zhumabek
2020-2-10
KSSV
2020-2-11
+1 ...I tried without using loop....it didn't flash in my mind that time.
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