A is a matrix of size 3232.I want to subtract elements of each 44 block of A from their respective 4*4 means

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bidlee devi 2020-2-12

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评论： Matt J 2020-2-13

A is a matrix of size 32*32. out = blockproc(A,[4 4],@(x)mean(x.data(:)));

Using the above code, I am able to reduce A to 8*8 which is obtained by averaging each 4*4 blocks of A. Now, I want to subtract elements of each 4*4 block of A from their respective 4*4 means. Thanks !

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采纳的回答

Matt J 2020-2-12

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编辑：Matt J 2020-2-12

out = blockproc(A,[4 4],@(x)mean(x.data(:)));
result = A - repelem( out , 4,4);

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bidlee devi 2020-2-13

After running the code

result1 = A - repelem( out , 4,4);

It says

"Undefined function 'repelem' for input arguments of type 'double'."

Matt J 2020-2-13

Upgrade!

https://www.mathworks.com/help/matlab/ref/repelem.html#bum31rc-1_seealso

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更多回答（1 个）

Fangjun Jiang 2020-2-12

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编辑：Fangjun Jiang 2020-2-12

A=rand(32);
out = blockproc(A,[4 4],@(x)mean(x.data(:)));
temp=repmat({ones(4,1)},8,1);
temp=blkdiag(temp{:});
Result=A-temp*out*temp'
%% or run below to see the effect
temp*magic(8)*temp'