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Averaging hour value of a timetable

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Hammad Khan
Hammad Khan 2020-2-16
评论： Steven Lord 2020-9-25
I am new to MatLAB and wanted help. I have hourly precipitation data of a certain place for 30 years (total values/rows=30*365*24=262800). Is there any way i can average values of each hour and generate a new vector having only 12 rows? In other words average of every value located 8640 rows apart.Thanks

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回答（1 个）

Akira Agata
Akira Agata 2020-2-17
How about the following solution?
% Create sample timetable
Time = datetime(2019,1,1,0,0,0) + hours(0:239)';
Value = rand(240,1);
TT = timetable(Time,Value);
% Calculate average value for each hour
[Group, Hour] = findgroups(TT.Time.Hour);
AvgValue = splitapply(@mean, TT.Value, Group);
tResult = table(Hour,AvgValue);
The result will be like this:
>> tResult
tResult =
24×2 table
Hour AvgValue
____ ________
0 0.61649
1 0.51445
2 0.32941
3 0.60418
4 0.53319
5 0.39934
6 0.41297
7 0.42935
8 0.48803
9 0.50767
10 0.55387
11 0.49949
12 0.59754
13 0.43441
14 0.40604
15 0.40547
16 0.37117
17 0.4985
18 0.5161
19 0.52695
20 0.2493
21 0.66763
22 0.57555
23 0.69638
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Eric Beamesderfer
Eric Beamesderfer 2020-9-25
atmosfera - I had a similar question. I am looking at a full year of data and trust my timeseries (don't need a solution involving a timetable), so here's what I ultimately did for half-hour data (non-leap year):
Steven Lord
Steven Lord 2020-9-25
Use retime with a NEWTIMES input spaced at half an hour intervals and an aggregation method of 'mean'.
newtimes = datetime('now') + hours(0:0.5:6);
If you're doing this outside the context of a timetable, use timeofday to get the elapsed time since midnight and discretize that duration array using a vector of edges created using hours like I did above.

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